0.2+x^2=14x

Solution for 0.2+x^2=14x equation:

0.2+x^2=14x

We move all terms to the left:

0.2+x^2-(14x)=0

a = 1; b = -14; c = +0.2;
Δ = b2-4ac
Δ = -142-4·1·0.2
Δ = 195.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-\sqrt{195.2}}{2*1}=\frac{14-\sqrt{195.2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+\sqrt{195.2}}{2*1}=\frac{14+\sqrt{195.2}}{2}
$